of silicon with ions of phosphorus, cach of mass mp- 5.18 x1 kg. The phosphorus
ID: 1870899 • Letter: O
Question
of silicon with ions of phosphorus, cach of mass mp- 5.18 x1 kg. The phosphorus ions are doubly ionized, with each phosphorus ion lacking two electrons. The ions start at rest at one end of the vacuum chamber and are accelerated by an electric field over a distance of = 59 cm before they strike the silicon layer with velocity vr-185 ms Randomized Variables Assignment Status Click here for detailed view e 59 cm p 185 m/s 33% Part (a) Enter an expression for the potential difference V, in volts, between the initial and final points across the vacuum chamber. Problem Status 1 Completed 2 Completed 3 Completed Grade Summary Deductions Potential 2% 98% 5 Partial 6 Completed 7 Completed 789 HOME 4 5 6 per attempt detailed e 256 mp BACKSPACE CLEAR Hints:% deduction per hint. Hn Hints remaining: Feedback: dedaction er 33% Part (b) Calculate the average electric field strength E, in volts per meters, across the vacuum chamber 33% Part (c) Calculate the average electric force F, in newtons, that the electric field exerts on each phosphorus ionsExplanation / Answer
We know that,
W = q V => V = W/q
W = 1/2 m v^2 = 1/2 mp vp^2
V = 1/2 mp vp^2/q
Or
q = 2 e
V = 0.5 mp vp^2/2 e
b)V = 0.5 x 5.18 x 10^-26 x 185^2/2 x 1.6 x 10^-19 = 2.77 x 10^-3 V
E = V/d = 2.77 x 10^-3/0.59 = 4.69 x 10^-3 V/m
Hence, E = 4.69 x 10^-3 V/m
c)Force = q E
F = 2 x 1.6 x 10^-19 x 4.69 x 10^-3 = 1.5 x 10^-21 N
Hence, F = 1.5 x 10^-21 N
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