Help Homework 3 Begin Date: 1/22/2018 12:00:00 AM -- Due Date: 2/12/2018 11:59:0
ID: 1871444 • Letter: H
Question
Help Homework 3 Begin Date: 1/22/2018 12:00:00 AM -- Due Date: 2/12/2018 11:59:00 PM End Date: 2/12/2018 11:59:00 PM (8%) Problem 8: A baseball slugger hits a pitch and watches the ball fly into the bleachers for a home run, landing h = 7.5 m higher than it was struck, when visiting with the fan that caught the ball, he learned the ball was moving with final velocity Vf= 31.95 m/s at an angle ,-255° below horizontal when caught. Assume the ball encountered no air resistance, and use a Cartesian coordinate system with the origin located at the ball's initial position V ©theexpertta.com 25% Part (a) Create an expression for the ball's initial horizontal velocity, vox in terms of the variables given in the problem statement 25% Part (b) Calculate the ball's initial vertical velocity, , in m/s × 25% Part (c) Calculate the magnitude of the ball's initial velocity, vo, in m/s Grade Summary Deductions Potential v.-31 .9501 0% 100% 789 HOME , 4 5 6 Submissions Attempts remaining: 2 (090 per attempt) detailed view cosO tan() ( cotan0 asin) acos0 sinh0 cotanhO atan)acotan() 0% 0% 0% 0% 0 END Degrees -Radians BACKSPACE DEL CLEAR Submit Hint Feedback I give up! Hints: 2% deduction per hint. Hints remaining: 3 Feedback: 2% deduction per feedback D 25% Part (d) Find the angle 0 in degrees above the horizontal at which the ball left the bat.Explanation / Answer
(A) horizontal velociy does not change as there is not acceleration in horizontal.
v0x = vfx = vf cos(theta_f)
(B) in vertical,
vf^2 - vi^2 = 2 a d
(vf sin(theta_f))^2 - (v0y)^2 = 2(- g ) (h)
v0y = sqrt[ 2 g h + (vf sin(theta_f))^2 ]
v0y = sqrt[(2 x 9.8 x 7.5) + (31.95 sin25.5)^2]
v0y = 18.3 m/s
(C) v0x = 31.95 cso25.5 = 28.8 m/s
v0 = sqrt(v0x^2 + v0y^2) = 34.2 m/s
(D) theta0 = tan^-1(v0y / v0x) = 28.2 deg
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