Data Table 2 Body moving down to a crouch Apparent True TW Flat line (on the pla

Question

Data Table 2 Body moving down to a crouch Apparent True TW Flat line (on the plate) SO GSo Downward trough sso 6So Acceleration- (AW-TW)/m, and its direction (up or down) Fictitious force (N)- Wt. (N Wt. (N)AW-TW, and its direction AW (up or down) due to inertia Upward peak Data Table 3 Body moving upward to standing Acceleration (AW-TW)/m, and its direction (up or down) ApparentTrue Fictitious force (N Wt. (N) Wt. (N) AW-TW, and its direction (up or down) due to inertia Flat line (on the plate) Upward peak Downward troughJ082SM 82 23 1. Data Table 2 a) Why does the measured force (AW) decrease as you start to lower your body?

Explanation / Answer

To find the acceleration in all cases, we need to find the mass of the body.

true weight (TW) of the body is 650 N in table 2. Mass of the body is

m= W/g= 650/10=65 kg

Now use this value of m(mass) to calculate the acceleration((AW-TW)/m).

Similarly, for table 2, the TW of the body is 825 N.

Mass m of the body is = TW/g= 825/10=82.5 kg

Use this value of m to find the accleration in each case.

I hope the solution helps. In case of further queries, please comment.

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