Two genes ( g and f ) are linked and are 40 map units apart. If a heterozygote p

Question

Two genes (g and f) are linked and are 40 map units apart. If a heterozygote parent with the alleles in trans (repulsed)is crossed to a homozygous mutant parent; what are the expected phenotypic classes and their ratios in the F1?

F1: g + (50%) + f (50%)

F1: g + (25%) + f (25%) g f (25%) + + (25%)

F1: g + (30%) + f (30%) g f (20%) + + (20%)

F1: g + (20%) + f (20%) g f (30%) + + (30%)

F1: g + (50%) + f (50%)

F1: g + (25%) + f (25%) g f (25%) + + (25%)

F1: g + (30%) + f (30%) g f (20%) + + (20%)

F1: g + (20%) + f (20%) g f (30%) + + (30%)

Explanation / Answer

distance between the linked gens is equivalent to recombinant frequency of the progengy and we get equal percent of recombinants.

here i this case 40 map unit apart means after crossing they give 40% of recombinant frequency and 60% of parental progengy . So, after crossing F1 progengy has:

g+(30%) + f(30%) gf(20%)++ (20%)

parental (60%) recombinant(40%)

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