Help on question 1 and 2. Thanks 1. 17. *·CE Figure 20-27 shows a series of equi
ID: 1872524 • Letter: H
Question
Help on question 1 and 2. Thanks 1. 17. *·CE Figure 20-27 shows a series of equipotentials in a particu- lar region of space, and five different paths along which an elec- tron is moved. (a) Does the electric field in this region point to the right, to the left, up, or down? Explain. (b) For each path, in- dicate whether the work done on the electron by the electric field is positive, negative, or zero. (c) Rank the paths in order of increasing amount of work done on the electron by the electric field. Indicate ties where appropriate. (d) Is the electric field near path A greater than, less than, or equal to the electric field near path E? Explain. 2. A. Rank the forces acting on each charge with the least first. Indicate ties with an equal sign There are regions where the electric field could be zero with this arrangement of charges. Are these between A and B, between B and C, to the left of A or the right of CExplanation / Answer
1) the value of electric potential decreases as we move in the direction of electric field, means electric field must point to left.
2) force exerted on an electron is opposite to the direction of electric field, therefore electric field does positive work on an electron that moves opposite in direction to electric field. hence work done along the paths have following sign:
A-positive, B-positive, C-positive, D-negative, E-negative
c) The work done by the electric field is proportional to the difference in the electrical potential between the starting and the end points of the path. thus dV for each case is :
A= +5 V, B= +40 V, C= +35 V, D= 15 V and E= 25 V
hence the ranking is E<D<A<C<B.
d) The magnitude of electric field is proportional to the magnitude of potential difference divided by the distance. The distance for path A and E are same, but the magnitude of potential difference is greater for E than A . hence,the electric field near path A is less than near path E.
2) force on A and C will be same, but less than B, hence order is A=C, B
3) Electric field will be zero in between B and C
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.