(8c4p2) A watermelon has the following coordinates: x--5.0 m, y-3.0 m, and z-0.0
ID: 1872583 • Letter: #
Question
(8c4p2) A watermelon has the following coordinates: x--5.0 m, y-3.0 m, and z-0.0 m. Find its position vector in terms of the vector's magnitude and orientation. Magnitude? Submit Answer Tries 0/8 Angle (ino deg) as measured counterclockwise from the x-axis Submit Answer Tries 0/8 Sketch the vector on a right-handed coordinate system. If the watermelon is moved to the x y z coordinates 5.0 m, 0.0 m, 0.0 m), what is its displacement in unit-vector notation? i-component? Submit Answer Tries 0/8 component? Submit Answer Tries 0/8 k-component? Submit Answer Tries 0/8 What is its displacement in terms of a magnitude? Submit Answer Tries 0/8 What is its displacement in terms of orientation? Submit Answer Tries 0/8Explanation / Answer
magnitude = sqrt(x^2 + y^2 + z^2)
= 5.8 m .....Ans
direction = 180 - tan^-1(3/5) = 149 deg .....Ans
i - compo = 5 m ....Ans
j -compo = 0
k - compo = 0
displacement magnitude = 5 m
direction angle (orientation) = 0 deg
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.