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iscms/mod/ibis/vi 9|Login | East Central Uni."-Cournel Shore Ercu East qotral Universi-× Jum ty-PHYS 1214 Spring18-WILLIAMS Activities and Due DatesHW: Electric Charge and Electric Field 6/2018 09:00 AM 0/15 Gradebook Balalator -Print n 1 of 15 -Periodic Table Sapling Learning Map A uraniun and iron atom reside a distance R- 26.90 nm apart. The uranium atom is singly ionized, the iron atom is doubly ionized. Calculate the distance r from the uranium atom necessary for an electron to reside in equilibrium.Ignore the insignificant gravitational attraction between the particles Number uranium ion ron ion electron What is the magnitude of the force on the electron from the uranium ion? Number

Explanation / Answer

The coulumb force between uranium and electron is

F1 = k qU qe/ r^2

The coulumb force between iron and electron is

F2 = k qFe q e/ ( 26.90 * 10^-9 - r)^2

at equilibrium F1= F2

qU = +1.602 x 10^-19 C

qFe = +2 x 1.602 x 10^-19 C

qe=-1.602 x 10^-19 C

(9*10^9 *(1.602*10^-19)^2/r^2 =(9*10^9 *2*1.602*10^-19 *1.602*10^-19)/(26.90 * 10^-9-r)^2

1/ r^2 = 2/(26.90 * 10^-9-r)^2

(26.90 * 10^-9-r)^2/ r^2 = 2

26.90* 10^-9 - r/ r = sqrt 2

26.90 * 10^-9- r = 1.414 r

r = 1.14 * 10^-8 m or 11.14 nm

(b)

F 1 = (9* 10^9) ( 1.6* 10^-19)^2/ (11.14* 10^-9)^2 = 0.185 * 10^-11 N or 1.85 * 10^-12 N

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