Return to Blackboard Cutnell, Physics, 10e PRINTER VERSION BA Chapter 01, Proble

Question

Return to Blackboard Cutnell, Physics, 10e PRINTER VERSION BA Chapter 01, Problem 32 GO jogger travels a route that has two parts. The frst is a displacement A of 2.70 km due south, and the second involves a displacement 8 that points due east. The resultant displacement A 8 has a magnitude of 4.75 km. (a) What is the magnitude of B and (b) what is the direction of A 8 as a positive angle relative to due south? Suppose that A B hada magtude of 475 km. (c) What ten would be the magntude of B,and (d) what is the direction of A· B relative to due south? (a) Number Units (b) Number Units em 13 () Number m) (d) Number tee Click if you would like to Show work for this geestions Units Units OomShamrX

Explanation / Answer

Q1 22.60

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A = - 2.70j

B = r i

R = A + B

|R| = sqrt(2.70^2 + r^2) = 4.75^2

r = 3.91 km

(A) |B| = r = 3.91 km

(C) A + B = 3.91 i - 2.70 j

theta = tan^-1(3.91/2.70) = 55.4 deg  

(D) A - B = -2.70j - r j

magnitude = (2.70^2 + r^2) = 4.75^2

r = 3.91 km

Ans: 3.91 km

(E )theta = tan^-1(3.91/2.70) = 55.4 deg

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