The f penguin has mass 5 k At one point, the heavier penguin starting from rest,

Question

The f penguin has mass 5 k At one point, the heavier penguin starting from rest, begins sliding frictionlessly down the slope. At the same time, the lighter penguin, starting from higher up the slope launches itself down the slope with a speed of 14 m/s 9) What is the total momentum of the two penguins immediately after their collision? It catches up to the heavier penguin after 3 seconds, both penguins then collide and, slide together down the hill. Immediately after the collision the pair of penguins is moving All Answers 10) What is the heavier penguin's momentum just before the collision Submit All Answers i 1) what was the lighter penguin's monnentum just before colliding with the heavier one? Submit Al 12) How fast did the lighter penguin launch itself down the slope? Answer 13) How much total impulse was exerted on the two penguins by gravity before the collision? Answer: Al Answers

Explanation / Answer

A);total momentum=total mass * velocity

={10+5) * 14=15*14=210 kg.m²/s²

B):heavier penguins momentum before collision

Velocity of heavier penguin.

As it started from rest,so initial velocity,u=0

Acceleration=gsinx where x=12°

And collision took place after 3 sec,so we have from equation of motion

V=U+at

V=0+gsin12 * 3=2.037*3=6.112 m

So momentum is

Mass*velocity before collision

Momentum=10*6.112

=61.12

C):as momentum is conserved

momentum before collision remains equal to momentum after collision.

Let momentum of lighter penguin before collision be M,then we have

M+61.12=210

M=148.88kg.m²/s².

From part c we have velocity of lighter penguin v,

148.88=5*v

V=29.776 m

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