1/2 points 1 Previous Answers OSColPhys1 19 P.029 Tutoria WA My Notes Ask Your T

Question

1/2 points 1 Previous Answers OSColPhys1 19 P.029 Tutoria WA My Notes Ask Your Teacher O A charge q1-242 c is at a distance d-1.53 m from a second charge q2--SS7 pe (a) Find the electric potential at a point A between the two charges that is d/2 from q1. Note that the location -37058.82 V (b) Find a point between the two charges on the horizontal line where the electric potential is zero. (Enter A in the diagram above is not to scale. your answer as measured from q1) 0.664 to be zero, what condlusion can you draw about the individual potentials at that location due to a1 and qz2? m 28 Tutorial Supporting Materials Physical Constants

Explanation / Answer

b)Let the point be x from q1

for the potential to be zero at this point

V1 = V2

k q1/x = k q2/(d - x)

2.42 x 10^-6/x = 5.57 x 10^-6/(1.53 - x)

2.42 (1.53 - x) = 5.57 x

3.70 = (2.42 + 5.57) x => x = 0.46 m

Hence, x = 0.46 m (from q1)

[A check, 2.42/0.46 = 5.57/(1.53 - 0.46)]

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