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Print by: JAMES SIMION Physics 202-001 Spring 2018/ DiFabio Phys 202 Chapter 22

ID: 1873043 • Letter: P

Question

Print by: JAMES SIMION Physics 202-001 Spring 2018/ DiFabio Phys 202 Chapter 22 part 2 *Chapter 22, Problem 052 An electron enters a region of uniform electric field with an initial velocity of 63 km/sin the same direction a electric field, which has magnitude E 50N/C)(a) what is the speed of the electron 1.7 ns after entering this region? (b) How far does the electron travel during the 1.7 ns interval? 1(1500G-1 Units (a) Number (b) Number [ Units * 2 Answer *1: the tolerance is +/-290 Answer *2: the tolerance is +/-290 .296 1,28 x lo-5 Question Attempts: Unlimited

Explanation / Answer

a)

vi = 63 km/s = 63000 m/s

a = q*E/m

= (-1.602*10^-19)*(50)/(9.11*10^-31)

= -8.79*10^12 m/s^2

t = 1.7 ns = 1.7*10^-9 s

use:

vf = vi + a*t

= 63000 + (-8.79*10^12)*(1.7*10^-9)

= 63000 - 14947

= 48053 m/s

Answer: 48053 m/s

b)

use:

vf^2 = vi^2 + 2*a*d

48053^2 = 63000^2 + 2*(-8.79*10^12)*d

2*(8.79*10^12)*d = 1.66*10^9

d = 9.44*10^-5 m

Answer: 9.44*10^-5 m

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