(a) (See Fig. 1a). What is the magnitude and direction of E-field at point P? (N
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Question
(a) (See Fig. 1a). What is the magnitude and direction of E-field at point P? (No need to calculate the magnitude in detail, just express whether it is zero or non-zero and justify why) (b) (See Fig. 1a). What is the magnitude of Potential at point P? (No need to calculate the magnitude, just express whether it is zero or non-zero and justify why). (c) (See Fig. 1b). Equipotential surfaces are shown in the Figure. How much work is required to move a test charge of 2 Coulombs from point “a" to point "b"? Express your answer in Joules. (d) (Not related to Fig. 1a or 1b) A small "negative" test charge is initially at rest in an electric field, and is free to move. Would the charge move towards higher potential or lower potential? Justify your answer. +Q :03 +Q 10V 30V 50V 70V90V Point P -Q Figure 1a -Q Figure 1bExplanation / Answer
a) The electric field at point P will be non zero as we will have components of electric field with distance of s2 / 2 between each charge and point P. We need to find components of electric field from each charge then add them up.
b) Potential at P will be zero as the potential from each corresponding charge will cancel out.
V = k ( q/r + q/r - q/r - q/r)
V = 0
C) W = qV = 2*(70-30) = 80 J
d) A negative charge will move towards region of higher potential
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