Consider the two systems of blocks and pulleys shown below. The surfaces are smo

Question

Consider the two systems of blocks and pulleys shown below. The surfaces are smooth, the pulleys are frictionless and the only forces applied are those due to gravity. Knowing you can't push on a rope, which systems will develop "slack" in the rope (a negative tension)? m2 1m1 m1 m2 The one on the right will go slack, but the one on the left will keep tension in the cable. Both will maintain tension. Both will go slack. The one on the right will keep tension on the cable, but the one on the left will go slack.

Explanation / Answer

Option -4 is the right answer..

Accoring to Newton's law, F = ma, i.e gravitaion force depends upon the mass. i.e more the mass, more the gravitaional forrce.

In the present case, m1 > m2 , So the gravitaion force on mass-1 is more than mass-2.

Again the sliding surface is smooth i.e. No friction force.

When the system of masses & pulley system is left on smooth surface, the heavier mass m-2 undergo the more gravitational force, there by, slide faster than the lesser mass-m1.

When the mass-2 at the bottom, it gives tension in the cable, and when it on top, it doesn't give tension to cable.

Therefore, "the one on the right will keep tension on the cable, but the one on the left will go slack"

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.