12) Using the attached data plot for the \"Sample Acceleration of the Cart\" exp
ID: 1873850 • Letter: 1
Question
12) Using the attached data plot for the "Sample Acceleration of the Cart" experiment and all three graphs with the indicated times (A through E) answer the questions below Position A is at the bumper, Position E is back at the bumper uestions for Acceleration of the Cart graphCircle all positions that appl When is the cart the farthest up the ramp? When is the velocity of the cart zero? Where is the cart going uphill? Where is the cart going downhill? When is the cart's acceleration direction down the ramp? Which section has the greatest acceleration? A B C DE A B C D E B D B D B C D B D 13) Looking at the plot of acceleration vs, time, why is the plot a horizontal line? What does this tell you about the net force acting on the cart and the net force's magnitude and direction during one segment of motion between the collisions with the bumper? (ignore collisions with bumper) 14) Why is the acceleration positive between collisions with the bumper but negative at the collisions with the bumper? (assume down the ramp as the positive direction) 15) Why was the acceleration uphill greater than the acceleration downhill? 16)If we assume your ramp was at an angle of about 3°and the net force acting on the cart going up-hill was nt different between the net force with frictions and without friction, what Fnet = mgsin + f, what perce does this tell you about the effect of friction on the cart? 17) Did your experiment verify the fact the acceleration up hill is greater than the acceleration downhill? Explain using your data. Page 3 of4Explanation / Answer
12) If A and E are positions of the bumper, then the cart is farthest on the ramp away from the bumper at C.
From velocity vs. time graph, we see that velocity is zero at C.
The cart is going uphill at B. A constant component of gravitational force acts on the cart at this point.
The cart is going downhill at D. A constant component of gravitational force acts on the cart at this point.
The acceleration is down the track at B C and D. See the accelaration vs. time graph, acceleration is constant at these points.
The acceleration is larger at B.
13) The acceleration vs. time graph is horizontal because a constant acceleration acts on the cart. The net force due to gravity that is acting on the cart is constant in magnitude and is directed down the ramp.
14) Since the direction of rate of change of velocity of the cart at collisions is directed up along the ramp, the acceleration is negative at collisions.
15) The force of friction is directed downwards for uphill motion and is directed upwards for downward motion. This leads to larger net force on the cart for uphill motion. So the acceleration is greater uphill.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.