(10pts) The electric field due to an infinite line of charge is perpendicular to
ID: 1874046 • Letter: #
Question
(10pts) The electric field due to an infinite line of charge is perpendicular to the line magnitude E·A/20. Co that has an infinite line of positive charge running along its axis. The charge per unit I line is = 4.00 pC /m. a) 6) nsider an imaginary cylinder with radius r = 0.260m and length 0.410m ength on the (6) What is the electric flux through the cylinder due to this infinite line of charge? b) (2) what is the flux through the cylinder if its radius is increased to r = 0.520m? 0.820m? c) (2) what is the flux through the cylinder if its length is increased toExplanation / Answer
electric field due to inifinite line of charge is
E = lamda/ 2pi eo r
formula for flux is
flux = E A cos theta
= lamda/ 2pi eo r * Acos thea
=lamda/ 2pi eo r * ( 2 pi rL) cos 0
=lamda * L/ eo
= 4 * 10^-6 *0.410/8.85 * 10^-12
=0.185 * 10^6 Nm^2/C
(b) at r = 0.520
as the charge inside the cyclinder will be same even if the radius is increased
flux =lamda * L/ eo
= 4 * 10^-6 *0.410/8.85 * 10^-12
=0.185 * 10^6 Nm^2/C
(c)
flux =lamda * L/ eo
= 4 * 10^-6 *0.820/8.85 * 10^-12
=0.37 * 10^6 Nm^2/C
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