along its length (at point P in the Firure) But, where to dig to fix in? The tel
ID: 1874050 • Letter: A
Question
along its length (at point P in the Firure) But, where to dig to fix in? The telephone cable is 6 00 km long aever trick which takes advantage of the fact that real wires do have a finite resistivity (so thesr resistance, while small, is not zero, and depends on lengthl) In order to determine where the cable, consisting of a pasr of wires, has suffered a short fist measuares the resistance between terminsals AB, then she measures the resistance across the terminals CD. The first measurement yields 95 00 Ohem, the second 10.00 Obm 6.00 kmExplanation / Answer
According to the concept of the current electricity
Resistance R=(resistivity) *L/A
Given that
Resistance R1=95 ohm
Resistance R2=10 ohm
Length L=6 km
Now we find the length where the short resistance is formed
Length L'=R2*L/R1=6000*10/95=631.6 m=0.6316 km
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