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along its length (at point P in the Firure) But, where to dig to fix in? The tel

ID: 1874050 • Letter: A

Question

along its length (at point P in the Firure) But, where to dig to fix in? The telephone cable is 6 00 km long aever trick which takes advantage of the fact that real wires do have a finite resistivity (so thesr resistance, while small, is not zero, and depends on lengthl) In order to determine where the cable, consisting of a pasr of wires, has suffered a short fist measuares the resistance between terminsals AB, then she measures the resistance across the terminals CD. The first measurement yields 95 00 Ohem, the second 10.00 Obm 6.00 km

Explanation / Answer

According to the concept of the current electricity

Resistance R=(resistivity) *L/A

Given that

Resistance R1=95 ohm

Resistance R2=10 ohm

Length L=6 km

Now we find the length where the short resistance is formed

Length L'=R2*L/R1=6000*10/95=631.6 m=0.6316 km

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