Problem 21.21 . 5 of 16 Part A Constants A 530-loop circular armature coil with

Question

Problem 21.21 . 5 of 16 Part A Constants A 530-loop circular armature coil with a diameter of 9.0 cm rotates at 190 rev/s in a uniform magnetic field of strength 0.70 T What is the rms voltage output of the generator? Express your answer to two significant figures and include the appropriate units Vrms =1 Value Units Submit Request Answer Part B What would you do to the rotation frequency in order to double the rms voltage output? O O To double the output voltage, you must double the rotation frequency. To double the output voltage, you must decrease by two times the rotation frequency. OTo double the output voltage, you must increase by four times the rotation frequency O To double the output voltage, you must treble the rotation frequency Submit Request Answer

Explanation / Answer

Part A

Vrms/phase=4.44*B*A*f*T

B=0.70T magnetic field

A=3.14*(.09)^2 meter2 area of loop

f= 190/sec frequency

T=530 number of turns

Vrms=7960.2 volt/phase

Part B

To double the output voltage, you must double the rotation frequency

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.