mat Toree 017 (part 1 of 4) 10.0 points A 40.6 kg box initially at rest is pushe
ID: 1874336 • Letter: M
Question
mat Toree 017 (part 1 of 4) 10.0 points A 40.6 kg box initially at rest is pushed 3.63 m along a rough, horizontal foor with a constant pointsa e block? if the coefficient of friction between box and foor is 0.477, find the work done by the applied force. The acceleration of gravity is ts ELin lico ,0.8 m/s2. gnitude 63.9NAnswer in units of J. 018 (part 2 of 4) 10.0 points the 63.9 N foxe Find the work done by the frictiorn Answer in units of 019 (part 3 of 4) 10.0 points Find the change in kinetic energy of the box er in units of J set of weights over his head, 020 (part 4 of 4) 10.0points · weight lifter do,Find the the final speed of the box. ghts at constantAnswer in units of m/s ) 021 10.0 points A block of mass m is pushed a distanee D up an inclined plane by a horizontal force F. The ch a Hooke's-lawplane is inclined at an angle 0 with respect to 4 N as we stretchthe horizontal. Ihe block starts from rest and .0 points kinetic friction is uk 0.0 points ching thc spring. 10.0 uointExplanation / Answer
a.
Work Done by the force
W = F * x = 199.789 * 3.63
= 725.234
B. Work done by the friction
W = umg = 0.477 * 40.6 * 9.8
= 189.78
C,
intenal energy of box
Uf = umgx = 189.78 * 3.63 = 688.94
Change in KE = 725.234 - 688.94 = 36.294 J
D.
Final Speed
V = sqrt ( 2 * KE / m )
= sqrt ( 2 *36.294 / 40.6 )
= 1.337 m/s
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