A 660 N cat burglar is supported by cables in the figure below. Assume the angle

Question

A 660 N cat burglar is supported by cables in the figure below. Assume the angle of the inclined cable is 34.00. (a) Find the tension in each cable inclined cable 530-1x Your response differs from the correct answer by more than 10%. Double check your calculations. N 560 0 horizontal cable Your response differs from the correct answer by more than 10%. Double (heck your calculations. N vertical cable (b) Suppose the horizontal cable were reattached higher up on the wan. would the tension in the inclined cable increase, decrease, or stay the same? increase decreas stay the same

Explanation / Answer

Here let the tension in the string be T.

From the diagram we have

Tsinx=along vertical which balances the weight

Tsinx=660

As x=34°

Tsin(34°)=660

T*0.5592=660 along the vertical.

And we have

T=660/0.5592=1180.257N

As complete T acts along incline, we have tension along incline=1180.257N.

Along horizontal we have the cos component of the tension

Th=Tcosx

Th=1180.257*cos(34)

Th=978.47N.

B):here the string balances only the horizontal component of tension.if it is tied higher in the wall and the weight is acting at the same point as it was earlier, string will become inclined and then it will balance a vertical part of tension also and thus net tension in the right inclined string decreases.

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