dep 18291781409 s tored in the 2.50- is stored in the capacitors in the figure b
ID: 1874707 • Letter: D
Question
dep 18291781409 s tored in the 2.50- is stored in the capacitors in the figure below (G-0.243 pEG-18.7neox capacitor? (Enter your answer to at least three significant figures.) 4 30e-04 What is the potential difference across the entire combination? What is the potential difference across the 2.50 jif capacikor compared to the potential difference across the combination? What is the potential difference across the series combination compared to the potential diference across the 2.50 JF capacitor? J Ci 250pF Additional Materials eBook Tutorial My Notes Ask Your 1 0 03 points Both capacitors have the same plate area of 3.30 cm2 and Two parallel-plate capacitors C1 and Ca are connected in series to a batteryExplanation / Answer
U3 = 1.8*10^-4 J = (1/2)*C3*V3^2 = (1/2)*Q3^2/C3
(1/2)*C3*V3^2 = 1.8*10^-4
(1/2)*2.5*10^-6*V3^2 = 1.8*10^-4
potential across C3 , V3 = 12 V
charge on C3 = Q3 = C3*V3 = 2.5*10^-6*12 = 30*10^-6 C
C1 and C2 are in seires
1/C12 = 1/C1 + 1/C2
1/C12 = 1/(0.243*10^-6) + 1/(18.7*10^-6)
C12 = 0.240*10^-6 F
potential across C12 = V3 = 12 V
energy in C12 = U12 = (1/2)*C12*V12^2 = (1/2)*0.24*10^-6*12^2 = 1.728*10^-5 J
total energy = 1.728*10^-5 + 1.8*10^-4 = 1.973*10^-4 J <<<<<--------ANSWER
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.