q Please help us improve Firefox and the Web Tell me more 11.P018 WI My Notes O

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Please help us improve Firefox and the Web Tell me more 11.P018 WI My Notes O Ask A counterweight of mass m 5.30 kg is attached to a light cord that is wound around a pulley as shown in the figure below. The pulley is a thin hoop of radius R 7.00 cm and mass M 1.10 kg. The spokes have negligible mass (a) What is the net torgue on the system about the axle of the pulley? magnitude N·m direction Select pulley has an angular speed -VR. Determine the magnitude of the total angular momentum of the system about (b) When the counterweight has a speed v, the axle of the pulley. kg·m)/ (c) Using your result from (b) and - di./dt, calculate the acceleration of the counterweight. (Enter the magnitude of the acceleration.) m/s Need Help? Read it

Explanation / Answer

Torque on the system = mgR
                                   = 5.3*9.8*0.07
                                      = 3.64 Nm
direction is anticlockwise when seen from right side.

b) Total angular momentum = mvR + MR2w
                                             = mvR + MRv
                                             = (m+M) Rv  

c) torque = dL/dt
               = (m+M)R dv/dt
               = (m+M)R a   ( where a is acceleration of mass m)
a = torque / (m+M)R

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