Need the steps for 5 and 6 5. Calculate the distance during the interval 2-5 sec

Question

Need the steps for 5 and 6 5. Calculate the distance during the interval 2-5 seconds. If the object is moving with a velocity of 5.o m/s east at 2 seconds, what is the final velocity of the object at 5 seconds? What is the the acceleration of the object? it the object is located 7.0 meters east of the oarigin at 5 n at 5 seconds, what was the location of the object at 2s? V (m/s) 100 80 60 40 20 6. Calculate the speed at the end of of 4 seconds. Which type of velocity did you calculate? If ty is not zero and at 4 seconds, the speed is 120m/s, what was the speed at Os? How far does the object move during this time? Acceleration (m/s)/s 10 m/s/s 4s S

Explanation / Answer

5. from the given graph

t = 2.5 s

area under graph will give us the distance

A = 2.5*40 = 100 m

as V is constant, final celocity is still 40 m/s

aceleration = 0

location at 2 s = 7 - 3*40 = -113 m west of the origin

6. given

a= 10 m/s/s

v(4) = 120 m/s

hence

v = u + at

120 = u + 10*4

u = 80 m/s

sped at 0 sec = 80 m/s

s = 80*4 + 0.5*10*16 = 400 m

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