h 22 HW Gauss\'s Law ercise 22.4 8 of 25> Part A Constants It was shown in Examp

Question

h 22 HW Gauss's Law ercise 22.4 8 of 25> Part A Constants It was shown in Example 21.11 (Section 21.5) in the textbook that the electric field due to an infinite line of charge is perpendicular to the line and has magnitude EA/2gr. Consider an imaginary cylinder with a radus ofr=0140 m and a length ofl:0425 m that has an rfrine line of positive charge running along its axis. The charge per unit lerigth on the ine is A+ 5.10 pC/m is the electric flux through the cylinder due to this infinite line of charge? N m2/C Submit PartB What is the flux through the cylinder if its radius is increased to r 0.555 Submt Part C What is the fux through the cylinder if its length is increased to 0.925 m ? N-m2/C O Type here to search 3)

Explanation / Answer

(A) electric flux = Qin / e0

Qin = lambda L

flux = (5.10 x 10^-6 x 0.425) / (8.854 x 10^-12)

= 2.45 x 10^5 N m^2 / C  

(B) independent of radius.

flux = 2.45 x 10^5 Nm^2/ C

(C) flux = (5.10 x 10^-6 x 0.925)/(8.854 x 10^-12)

flux = 5.33 x 10^5 N m^2 / C

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