please help thanks. Two loudspeakers, 3.5 m apart and facing each other, play id

Question

please help thanks.

Two loudspeakers, 3.5 m apart and facing each other, play identical sounds of the same frequency. You stand halfway between them, where there is a maximum of sound intensity. Moving from this point toward one of the speakers, you encounter a minimum of sound intensity when you have moved 0.29 m . Assume the speed of sound is 340 m/s. Part A What is the frequency of the sound? Express your answer to two significant figures and include the appropriate units. LA f-Value Units Submit Request Answer Part B If the frequency is then increased while you remain 0.29 m from the center, what is the first frequency for which that location will be a maximum of sound intensity? Express your answer to two significant figures and include the appropriate units. f-Value Units Submit Request Answer

Explanation / Answer

part A

at position 0.29 m first minimum is encountered m = 1

path difference between the two waves coming from speakers = (3.5+0.29)-(3.5-0.29) = 0.58 = m*lambda/2

0.58 = 1*lambda/2

wavelength , lambda = 1.16 m

frequency f = v/lambda = 340/1.16 = 293 Hz

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part B

at location 0.29 m second maximum soundy intensity occurs m = 1

for constructive interference

path difference = m*lambda = 0.58

1*lambda = 0.58 m

lambda = 0.58 m

frequency f = v/lambda = 340/0.58 = 586 Hz

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