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Three resistors R1 = 84.5 , R2 = 24.2 , R3 = 70.0 , and two batteries e m f1 = 4

ID: 1875990 • Letter: T

Question

Three resistors R1 = 84.5 , R2 = 24.2 , R3 = 70.0 , and two batteries e m f1 = 40.0 V, and e m f2 = 353 V are connected as shown in the diagram below.

(a) What current flows through R1, R2, and R3?


I1 =  
I2 =  
I3 =  

(b) What is the absolute value of the potential difference across R1, R2, and R3?

|VR1| =  

|VR2| =  

|VR3| =  

21J: Circuits c Secure ! https://wwww.webassign.net/web/Student/Assignment-Responses/last?dep=18317804 10. + -6 points OSColPhys2016 21.3.WA 033. My Notes Ask Your T Three resistors R1 = 84.5 , R2 = 24.2 , R3 = 70.0 , and two batteries ,-40.0 V, and ,-353 are connected as shown in the diagram below. Ri E1 (a) What current flows through R1, R2, and R3? (b) What is the absolute value of the potential difference across R, R2, and R3? Additional Materials Reading 3:40 PM

Explanation / Answer

let the current in R1 be I1 from bottom to top and let it be I2 in R2 from top to bottom

Applying KVL we got

E1+E2=I1*R1 +I2*R2=40+353=84.5I1+24.2I2..............(1)

current in R3 will be (I1-I2)

applying KVL we got

E2=I2*R2-(I1-I2)*R3=353=24.2I2-(I1-I2)*70

353=94.2I2-70I1...............(2)

solving (1) and (2) we got

I1=2.94 A

potential across R1=I1*R1=84.5x2.94=248.43 V

I2=5.93 A

potential across R2=I2*R2=24.2x5.93=143.50v

current in R3=I1-I2=5.93-2.94=2.99 V

potential across R3=I3xr3=2.99x70=209.3v

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