for number 1: round is R and wrinkled is r; green is Y and yellow is y. Braneh D

Question

for number 1: round is R and wrinkled is r; green is Y and yellow is y.

Braneh Diagrams .As discussed in lecture, and presented in your textbook, a branch diagram is a simple way of figuring out the outcome of a genetie cross without having to do a larger than 2x2 Punnett square. Refer to page 65 of your textbook if you need to review how to set up a branch diagram. Draw a branch diagram below to predict the phenotypic ratios for the following cross: RrYy x ryy. Write out the phenotype next to each of the four genotypic classes in the progeny using the round/wrinkled yellowgreen traits described on page 65. 2. You are told that a cross between two parents with genotype Rr, (where R- round seeds and r wrinkled seeds) resalts in the following progeny: 5474 round and 1850 wrinkled. Calculate a value for this data. Using Table 3.7 on page 68 of your textbook, what is the probability of obtaining these results? (Show your work in ful using a table to show values for observed expected ete.) Probability ofobtaining results" Accept or Reject Read the handout to answer the following question: 3. What would be the phenotype of a com kenel with the following genotype?

Explanation / Answer

Answer to Question-1:

Parents: RrYy X rryy

Gametes from Parent-1: RY, Ry, rY and ry.

Gametes from Parent-2: ry, ry, ry and ry.

F1 generation can be drawn using Punett square as follows:

Therefore, it is clear from the table above that phenotype in - column-1 have round green, column-2 have round yellow, column-3 have wrinkled green and column-4 have wrinkled yellow.

Genotypic ratio - 4:4:4:4

Thus, it becomes 1:1:1:1

Gametes RY Ry rY ry ry RrYy Rryy rrYy rryy ry RrYy Rryy rrYy rryy ry RrYy Rryy rrYy rryy ry RrYy Rryy rrYy rryy

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