Three charged metal disks are arranged as shown (cutaway view). The disks are he

Question

Three charged metal disks are arranged as shown (cutaway view). The disks are held apart by insulating supports not shown in the diagram. Each disk has an area of 2.3 m2 (this is the area of one flat surface of the disk). Use the value 8.85e-12 C2/(N·m2) for 0.The charge Q1 = 7e-8 coulombs, and the charge Q2 = 4e-7 coulombs.

What is the direction of the electric field between disks 1 and 2? ---Select--- +x -x +y -y +z -z

Which of the following statements are true? Choose all that apply.

To calculate VC - VB, which path should you choose?

A path starting at C and ending at BIt doesn't matter whether the path starts or ends at B     A path starting at B and ending at C

The sign of VC - VB should be:

What is the potential difference VC - VB?
VC - VB = _____ volts

What is the potential difference VD - VC?
VD - VC =  volts
What is the potential difference VF - VD?
VF - VD = ______ volts

What is the potential difference VG - VF? VG - VF =____ volts

What is the potential difference VG - VA? VG - VA = ____volts

The charged disks have tiny holes which allow a particle to pass through them. An electron which is traveling at a fast speed approaches the plates from the left side. It travels along a path from Ato G. Since no external work is done on the system of plates + electron,

K + U = Wext = 0

Consider the following states: Initial, electron at location A. Final, electron at location G.

What is the change in potential energy of the system?
U =_______ joules
What is the change in kinetic energy of the electron?
K =______ joules

Explanation / Answer

C = A/ d

for disk 1 and 2: C = *(2.2)/(0.004) = 8.85e-12*2.3/0.004 = 5.09e-9 F

V=Q1/C = 7e-8/5.09e-9 = 13.75 Volts

E|12| = V/d = 13.75/0.004 = 3.437e3 Volts/m

VC - VB = -13.75 volts

the potential difference VD - VC is zero because according to the Gauss' law the electrical field inside the metal is zero VD - VC = 0

for disk 2 and 3: C = *(2.3)/(0.0017) = 8.85e-12*2.3/0.0017 = 11.973e-9 F

V=Q2/C = 4e-7/11.973e-9 = 33.4 Volts

VF - VD = 26.19 Volts

the potential difference VG - VF is zero

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