Constant Total Mass Table (10 points) 88 6 46 0.0200 0.0800 6. 0.0250 10.0750|01

Question

Constant Total Mass Table (10 points) 88 6 46 0.0200 0.0800 6. 0.0250 10.0750|01-two, tos 0.0300 0.0700 0 0.0350 0.0650 0, Complete the above chart. Use the experimental acceleration to calculate the net fo error between the theoretical acceleration and the experimental acceleration for each run rce, and find the %

Explanation / Answer

s.no m1(kg) m2(kg) m1+m2 Aex(m/s^2) Fne(N) Ath(m/s^2) %=>(Aex/Ath)*100=x % 1 0.015 0.085 0.1 6.52 0.6 6.867 (6.52/6.867)*100=94.9% 2 0.02 0.08 0.1 5.61 0.6 5.886 (5.61/5.886)*100=95.35 3 0.025 0.075 0.1 4.68 0.5 4.905 (4.68/4.905)*100=95.4% 4 0.03 0.07 0.1 3.75 0.4 3.924 (3.75/3.924)*100=95.6% 5 0.035 0.065 0.1 2.77 0.3 2.943 (2.77/2.943)*100=94.1% s.no m1(kg) m2(kg) m1+m2 Aex(m/s^2) Fnet (N) Ath(m/s^2) (Aex/Ath)*100=x% 1 0.035 0.065 0.10 2.8 0.28 2.943 (2.8/2.943)*100=95.1% 2 0.04 0.07 0.11 2.54 0.28 2.675 (2.54/2.675)*100=94.95% 3 0.045 0.075 0.12 2.34 0.28 2.453 (2.34/2.453)*100=95.4% 4 0.05 0.08 0.13 2.17 0.28 2.264 (2.17/2.264)*100=95.8% 5 0.055 0.085 0.14 2.02 0.28 2.102 (2.02/2.102)*100=96.1%

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.