0/6.68 SEML1 6.Q 002 A 2.10 nF capacitor with an initial charge of 4.S5 HC is di

Question

0/6.68 SEML1 6.Q 002 A 2.10 nF capacitor with an initial charge of 4.S5 HC is discharged through a 1.18 kn resistor (a) Calculate the current in the resistor 9.00 s after the resistor is connected across the terminals (b) what charge remains on the capacitor after 8.00 s? (c) What is the maximum current in the resistor? lectronic presentatien to be used with SERWAYCEWETT. Phveics for Scentsts and Engineers wiens Moderm, avand iwen entaneed Physics for Scientists and Engineers with Modern, Hybrid Leth Enhanced webAssign Homework and eBook LOE Printed Access

Explanation / Answer

a)

We know that equation for current in discharging of capacitor is,

I=(V/R)e-t/RC

I=(Q/CR)e-t/RC

I=(4.55*10-6/2.1*10-9*1.18*103)e-9/2.1*1.18

I=0.04859A

b)

Charge on the capacitor after 8 micro seconds will be,

Q=Q0e-t/RC

Q=4.55e-8/2.1*1.18

=0.18 micro coloumb

c)

maximum current in the resistor is,

I=V0/R

=Q/CR

=4.55*10-6/2.1*10-9*1.18*103

=1.836A

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