Two identical conducting spheres, fixed in place, attract each other with an ele
ID: 1877224 • Letter: T
Question
Two identical conducting spheres, fixed in place, attract each other with an electrostatic force of 0.125 N when their center-to-center separation is 50.4 cm. The spheres are then connected by a thin conducting wire. When the wire is removed, the spheres repel each other with an electrostatic force of 0.0470 N. Of the initial charges on the spheres, with a positive net charge, what was (a) the negative charge on one of them and (b) the positive charge on the other? (Assume the negative charge has smaller magnitude.)
Explanation / Answer
here,
sepration , r = 50.4 cm = 0.504 m
let the two charges be q1 and - q2
the electrostatic force , F1= K * q1 * q2 /r^2
0.125 = 9 * 20^9 * q1 * q2 /0.504^2 ...(1)
when they are connected with a conducting wire
the charge on each sphere , q = ( q1 - q2)/2
the electrostatic force , F2 = K * q^2 /r^2
0.047 = 9 * 10^9 * q^2 /0.504^2
0.047 = 9 * 10^9 * ((q1 - q2)/2)^2 /0.504^2 ...(2)
from (1) and (2)
q1 = 3 * 10^-9 C
q2 = 2.31 * 10^-9 C
a)
the negative charge is - 2.31 * 10^-9 C
b)
the positive charge is 3 * 10^-9 C
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.