The velocity graph is shown for a particle having initial position x0=0m at t0=0

Question

The velocity graph is shown for a particle having initial position x0=0m at t0=0s.

At what time or times is the particle found at x = 20 m ? Work with the geometry of the graph, not with kinematic equations.

t2=10s

t1=6s and t2=8s t1=2s and t2=10s t1=4s

t2=10s

Problem 2.8 Part A The velocity graph is shown for a particle having initial position o 0 m at to 0s.(Figure 1) At what time or times is the particle found at x = 20 m ? Work with the geometry of the graph, not with kinematic equations. O t1=68and t2 = 88 O t1 2 s and t2=10 s t1 4 s t2 10 Figure 1 of 1 Submit (m/s) 10 Provide Feedback 01 r (s) 4 6810 12

Explanation / Answer

To find the position x, find the area under the v-t curve since

v = dx/dt

at t = 2s, x = vt = 10 x 2 = 20 m

Also, between t = 0s and t=10s,

x = 20 + (1/2)(10)(6-2) + (1/2)(-10)(10-6) = 20 + 0 = 20 m [answer - 2nd option].

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