3. Science uses the MKS system (SI System Internationale). MKS slands for meter,

Question

3. Science uses the MKS system (SI System Internationale). MKS slands for meter, kilogram, second. These are the units of choice of physics. The equations in physics depend on unit agreement. So you must convert to MKS in most problems to arrive at the correct answer kilameters (km) to meters (m) and meters to kilometers centimeters (em) to meters (mo and meters to centimeters millimeters (ame to meters (m) and meters to milimeters nanometers (nm) 10 meters ( and metes to nanometers micrometers (um) to meters (im) Other conversions will be taught as they become necessary gram ( to kiogram ( Celsius ("c) to Kelvin (K atmospheres (atm) to Pascals (Pa) iters (L) to eubic meters (m What if you don't know the conversion factors? Universities want students who can ind their own information (sc do employers) Enjoy h. 25.0m i 2.65 mmm b. c, d. 1.2 km 823 nm 298 k i 8.23 mkm t. 8.8x10 m 9. 1.2 atm Solve the following geometric problems. . 54L 1 40.0 cm m. 6.23x10 mm n. 1.5x10 m Pa 6. a. what is angle ? 30 b. How large is 6? 30 c. The radius of a circle is 5.5 cm i. What is the circumference in meters? ii, What is its area in sauare meters? d. What is the area under the curve at the right? 20 12

Explanation / Answer

a) 4008 g = 4.008 kg

b) 1.2 km = 1200 m

c) 823 nm = 823*10^-9 m

d) 298 K = 298 - 273

= 25 C

e) 0.77 m = 77 cm

f) 8.8*10^-4 m = 0.88 mm

g) 1.2 atm = 1.2*1.013*10^5 pa

= 1.2156*10^5 pa

h) 25.0 microm = 25.0*10^-6 m

i) 2.65 mm = 2.65*10^-3 m

j) 8.23 m = 8.23*10^-3 m

k) 5.4 L = 5.4*10^-3 m^3

l) 40.0 cm = 0.400 m

m) 6.23*10^-7 m 6.23*10^2 nm

n) 1.5*10^11 m = 1.5*10^8 km

6) theta = 180 - 30 = 150 degrees

b) theta = 90 - 30 = 60 degrees

c)

i) circumaference = 2*pi*r

= 2*pi*5.5

= 34.6 cm

= 0.346 m

ii) area = pi*r^2

= pi*5.5^2

= 95.0 cm^2

= 95.0*10^-4 m^2

d) area under the curve = 4*12 + (1/2)*(20 - 12)*4

= 64 square units

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