PHYS 2211 Pre-Lab Preparation: Motion in One Dimension Skim through the Motion i

Question

PHYS 2211 Pre-Lab Preparation: Motion in One Dimension Skim through the Motion in One Dimension lab in its enirety-t's aways good ides to have d nd n mind when you start a project 1. What are you going to be doing in this lab? 2. What equipment are you going to be using What daia will it recoed 3. Write the equations for the definitions of the following quantities displacement is Nothing but Chamge im oblect PosiHion time interval average velocity the gate at which dispaceNem+ Chamges i the vate at which velociry chang e average aceeleration 4. Your data will consist of position-time graphs like the following. (The LabQuest device will be able to show you velocity-time and acceleration-time graphs as well, but keep in mind that those are calculated from the position and time data, so even on the computer they are analysis rather than data!) In the data table, record the position of the graphed object every 2 s starting at t = 0 s. t (s)x (em) 0 10 2 50 50 6 30 130 10

Explanation / Answer

for time interval 0-2 s

xi corresponds to position x at t= 0 => xi = 70 cm

xf corresponds to position at t=2 => xf = 50 cm

Delx = xf - xi = 50-70 = -20

Vav = Delx/time diff = -20/(2-0) = -10 cm/s

As the velocity is constant in this region, the intial and final velocities will be equal to Vav = -10 cm/s

time interval 2-4

xi = 50 cm

xf = 35 cm

Delx = xf-xi = -15 cm

Vav = Delx/2 = -7.5 cm/s

Vinitial = V at 2 sec = -10cm/s

Vav = (Vinitial + Vfinal)/2

=> Vfinal = 2*Vav - Vinitial = -15 + 10 = -5 cm/s

for time interval 6-8 S

xi = 30 CM

xf = 30 cm

Delx = 0

=> Vav = 0

for time interval 8-10 sec

xi = 30

xf = 40

Delx = xf - xi = 10

Vav = Delx/2 = 5 cm/s

The velocity of the object is not constant over entire 10 sec because the slope of position vs time graph is changing (and also from the computations above)

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