T-Mobile Wi-Fi 9:30 PM 9 webassign.net Mariana finds a cave to explore. Starting
ID: 1878159 • Letter: T
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T-Mobile Wi-Fi 9:30 PM 9 webassign.net Mariana finds a cave to explore. Starting at the cave entrance, Mariana first follows a passage 75.0 m north, then turns and moves 250 m east, then goes 124 m at an angle 30.0 north of east, and finally moves 192 m south. Find the resultant displacement from the cave entrance. Shown is a sketch of the situation not drawn to scale. (Give the magnitude of the displacement in m and the direction in degrees south of east.) What is the resultan acement from the entrance? sourh of Need Help?ods It takes a golfer a total of three strokes to put the ball in the hole. The displacements of the three strokes are as follows: the north.,-2.00m northeast, and,-090 m at o. 350. west of south, as shown in the figure. If the golfer had made the hole in a single shot, what would be the displacement of the ball? (Assume the positive y- and x-axes are in the north and east directions, respectively. Give the magnitude of your answer in meters and the direction in degrees north of east.) magnitud 4.34 be east, and +y be north. Write each of the displacements in unit-vector notation. Note that "northeast" means 45° north of east Use the figure to help you determine the signs of the components, and sum the displacement vectors to find the total displacement. Then use the Pythagorean theorem to find the magnitude. m Birection 5north of east Need Help? bnu In a local bar, a customer slides an empty beer mug down the counter for a refill. The height of the counter is 1.18 m. The mug slides off the counterExplanation / Answer
the displacement of a person in North is ,
N = 75 + 124 X sin30 - 192
N = - 55 m
in east direction
E = 250 + 124 X cos30
E = 357.387 m
total dispalcement is
d = ( (-55)2 + 357.3872 )1/2
d = 361.594 m
angle = tan-1 ( - 55 / 357.387 )
angle = - 8.74o
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d1 = 3.9 j
d2 = 2 North east
= 1.41 ( i + j )
d3 = 0.9( cos240 i + sin240 j )
= - 0.45 i - 0.779 j
d = d1 + d2 + d3
d = ( 1.41 - 0.45 ) i + ( 3.9 + 1.41 - 0.779 ) j
d = 0.96 i + 4.531 j
magnitude is = ( 0.962 + 4.5312 )1/2 = 4.631 m
angle is = tan-1 ( 4.531 / 0.96 ) = 78.037o north of east
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