s. -15 points CJ10 19,P.0 0/4 Submissions Used My Notes A particle with a charge

Question

s. -15 points CJ10 19,P.0 0/4 Submissions Used My Notes A particle with a charge of -1.2 C and a mass of 3.5 10-6 kg is released from rest at point A and accelerates toward point B, arriving there with a speed of 43 m/s. The only force acting on the particle is the electric force. (a) Which point is at the higher potential? o point A o point B Give your reasoning. Negative charge accelerates from a higher potential to a lower potential. O Negative charge accelerates from a lower potential to a higher potential. (b) What is the potential difference VB VA between A and B? Additional Materials section 19.2

Explanation / Answer

a) Point B because negative charge acclerates from a lower potential to a higher potential

b) potential difference = Vb - Va

= qW

= 1.2*10^-6 * (0.5*3.5*10^-6*43^2)

= 3.88*10^-9 V

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