A ball is released from rest from a height h in the presence of uniform gravitat

Question

A ball is released from rest from a height h in the presence of uniform gravitational acceler- ation where g = 9.8 m/s2. The ball descends, strikes the ground, and bounces in such a way that its velocity is reversed with no loss of speed. If 2.40 seconds elapse between the release of the ball and its return, what is the height h from which the ball is dropped?
A ball is released from rest from a height h in the presence of uniform gravitational acceler- ation where g = 9.8 m/s2. The ball descends, strikes the ground, and bounces in such a way that its velocity is reversed with no loss of speed. If 2.40 seconds elapse between the release of the ball and its return, what is the height h from which the ball is dropped?
A ball is released from rest from a height h in the presence of uniform gravitational acceler- ation where g = 9.8 m/s2. The ball descends, strikes the ground, and bounces in such a way that its velocity is reversed with no loss of speed. If 2.40 seconds elapse between the release of the ball and its return, what is the height h from which the ball is dropped?

Explanation / Answer

for moving down:

a = -9.8 m/s^2

vi = 0 m/s

d = ?

t = 2.40/2 = 1.20 s

Use:

d = vi*t + 0.5*a*t^2

d = 0 + 0.5*(-9.8)*(1.20)^2

d = -7.06 m

d is negative because ball moved down

h = 7.06 m

Answer: 7.06 m

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