L WileyPLUS c eduigenwileyplus.com.edugen/lti/main.un. WileyPLUS Chabay, Matter

Question

L WileyPLUS c eduigenwileyplus.com.edugen/lti/main.un. WileyPLUS Chabay, Matter &Interactions, 4c PRINTER VERSIONB BACK ASSIGNMENT RESOURCES Problem 15.22 A plastic-Dd 1.3 lang is rubbed all over with wool, and acquires a charge of-9E-8 coulambs. we choose the center of the rod to be the origin of our coordinate system, with the x-axis extending to the right, the y-axis extending up, and the z-axis out or the page. [n order to calculate the electric teld at location A = m, we divide the rod into 8 pieces, and approximate each piece aspoint charge located at the center of the piece. Prabicm 15.21 j zero magnitude (a) What Is the length of one of these plecas? 0.65 (b) what is the location of the center of iece number 7? (c) Ho much charge is on piece number (Remember that the charge is negativa.) coulombs (d) Approximating plece 7 as a point charge, what is the electric fleld at location A due only to plece 7? N/C e) To get the net electric field at location A w would need ta calculete due each af the S pieces and add up these contributions If we dic that which arrow above would best re resent the direction of the net e ectric feld at location A? Type here to search 9/11/2018 10

Explanation / Answer

Given,

L = 1.3 m ; q = 9 x 10^-8 C ;

a)l = 1.3/8 = 0.1625 m

Hence, l = 0.1625 m

b)x = 0.1625 x 3.5 = 0.5688

<0,-0.5688,0>m

c)each section's charge = 9 x 10^-8/8 = 1.125 x 10^-8 C

Q = 1.125 x 10^-8 C

d)we know that

E = k q/r^2 r

r = sqrt (0.7^2 + 0.5688^2) = 0.902 m

E = 9 x 10^9 x 1.125 x 10^-8/0.902^2 = 124.45 N/C r(hat)

r(hat) = -0.7/0.902 , -0.5688/0.902 = <-0.78,-0.63>

E = 124.45 <-0.78,-0.63) = <-97.07,-78.4>

Hence, E = <-97.07,-78.4,0>

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