D Question 8 10 pts Calculate the magnitude of the electric field (in NC) at 2 8
ID: 1878481 • Letter: D
Question
D Question 8 10 pts Calculate the magnitude of the electric field (in NC) at 2 8 m from a point charge of 22 HC. You should round the answer to an integer, indicate only the number, do not include the unit Hint: 1pC 10-6C 2525.0000 DQuestion 9 10 pts What is the magnitude (in N C) and direction of an electric field that exerts a 2 x 10 N upward force on a-37 pC charge? luC 106c Indicate direction with a positive or a negative value Keep in mind that a positive vector is directed upwards and a negative vector is directed downwards on the y axis On the s axis, a positive vector is directed to the right and a negative vector is directed to the left Your answer should be a positiye or a negative number with two decimal places, do not include the unitExplanation / Answer
8.
r = distance from the point charge = 2.8 m
Q = magnitude of the point charge = 2.2 x 10-6 C
magnitude of electric field is given as
E = k Q/r2
E = (9 x 109) (2.2 x 10-6)/(2.8)2
E = 2525.5 N/C
Q-9
q = magnitude of charge = 3.7 x 10-6 C
E = electric field = 2 x 10-5 N/C
magnitude of electric force is given as
F = q E
F = (3.7 x 10-6) (2 x 10-5)
F = 7.4 x 10-11 N
since the charge is negative , the charge experience electric force inopposite direction of electric field. Since the electric force is in upward direction , the electric field must be in downward direction
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