$4 ite msu.edu section:733 PHY231C, Fall 2018-2 Messages Courses Help Logout A c

Question

$4 ite msu.edu section:733 PHY231C, Fall 2018-2 Messages Courses Help Logout A car is initially at rest on a straight road. The histogram below shows the cars acceleration along that road as a function of time. 123455718 1112 13 14 Cakulate the speed of the car at t -3s 5.00 m/s You are c Calculate the distance traveled during the first 5 s Cakulateth edistance traveled ren rsionfoundbetween Tries0/200us Incompatible units No conversion found between Tries 9/20 Previous Tries from t 11 s to t14s Tries 0/20 Pretous m/s. and the required units. ar's average speed from t-5sto t-9 s Submission not graded. Use more digits. Tries o/2 Previous Tries Export NEW Dtsr.nes NEW Last Twe Parts Dhirals Patel Re(ue Sep 11 04 0 47 om 201e (eoty I am struggling to ort the last two parts of the question

Explanation / Answer

ii] Since the car is initially at rest, its speed until t=1s is zero.

For determining the distance, use: S = ut + (1/2)at2

so, distance traveled in first 2 seconds is:

S = 0 + (1/2)(2)(1)2 = 1 m

in the first 3 seconds:

S = 1 + 2(1) + (1/2)(3)(1)2 = 4.5 m

the acceleration is zero from t=3 to t=4s

therefore, S = 4.5 + 5(1) = 9.5 m

finally, the distance traveled in the first 5 seconds is:

S = 9.5 + 5(1) - (1/2)(2)(1)2 = 13.5 m.

iii] Area under the curve until t = 10s gives the velocity at t=10s

v = 2 + 3 - 2 - 1 + 2 + 1 - (1 x 2) = 4 m/s

the acceleration at t=11s is 0 m/s2

therefore, distance traveled from t=11s to t=14s is:

D = vt = 4(14-11) = 12m.

iv] Distance at t=5s is: d = 13.5 m

similar to finding the distance at t=5s, calculate the distance d' at t=9s

so, average speed is: vavr = (d' - d)/(9 - 5) m/s.

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