edu x 099245-dt-content-rid-19817008 1/courses/NE-PHYS-302-01-201910/Pedot https

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edu x 099245-dt-content-rid-19817008 1/courses/NE-PHYS-302-01-201910/Pedot https//duq blackboard.com 28 Show that the lateral displacements of a ray of light pene213 aAt what position in front of a spherical refracting must an objoct be placed so that the refraction pr trating a rectangular plate of thickness t is given by parallel rays of light? In other words, what is the focal of a single refracting surface? b. Since real object distances are positive, what does where 6 and 6 are the angles of incidence and refraction, re- spectively. Find the displacement when t -3 cm,-1.0, 2-14 A small and 6 50 result imply for the cases nR and i 2-14 A small goldfish is viewed through a spherical glass bowl 30 cm in diameter. Determine the apparent posi and magnification of the fish's eye when its actual posit is (a) at the center of the bowl and (b) nearer to the oberv halfway from center to glass, along the line of sight.A 29 A meter stick lies along the optical axis of a convex mirror ot locall length 40 cm, with its nearer end 60 cm from the mir- or surface. How long is the image of the meter stick? sume that the glass is thin enough so that its effect on t refraction may be neglected. 2-10 A glass hemisphere is silvered over its curved surface. A small air bubble in the glass is located on the central axis through the hemisphere S em trom the plane surface. The 2-15 A small object faces the convex spherical glass window of dius of curvature of the spherical surface is 7.5 cm, and the glass has an index of 1.50. Looking along the axis into he plase surface, one sees two images of the bubble. How do they arise and where do they appear? small water tank. The radius of curvature of the window is cm. The inner back side of the tank is a plane mirror, 25 cm from the window. If the object is 30 cm outside the window, determine the nature of its final imago, neglecting any re- fraction due to the thin glass window itself Window -30 em__ 25 cm Figare 2-35 Problem 2-15 2-16 A plano-convex lems having a focal length of 25.0 cm is to be made with glass of refractive index 1.520. Calculate the radius of curvature of the grinding and polishing tools to be 2-u 3-13 A coecave miror forms an image on a screen twkoc a large used in making this lens object. Both object and sereen are thea moved to 2-17 Calculate the focal length of a thin meniscas lens whose spher- cal surfaces have radiu of curvature of magnitude 5 and 10 cm is the focal length of the The glass is of index 1.50. Sketch both positive and negative DELL FS F6 F7

Explanation / Answer

2-15:

1. When rays from the object will refracted through Spherical window:

Using Equation

n1/u + n2/v = (n2 - n1)/R

Given that

n1 = 1 & n2 = 4/3

u = object distance = 30 cm

R = 5 cm

So,

1/30 + 4/(3v) = (4/3 - 1)/5

4/3v = 1/15 - 1/30 = 1/30

1/v = 1/40

v = 40 cm = image distance from spherical window

2. Now rays will reflected back from plane mirror, So

Object distance for plane mirror will be

u1 = 25 - v = 25 - 40 = -15 cm

negative sign means object is virtual

Now image due to plane mirror will be

v1 = -(u1) = -(-15)

v1 = 15 cm = image distance from plane mirror

3.

Now the ry will refract out through spherical window, So again using formula of step 1

But this time, n1 = 4/3, & n2 = 1

u2 = object for spherical window = 25 - v1 = 25 - 15 = 10 cm

And this time R = -5 cm

So,

n1/u2 + n2/v2 = (n2 - n1)/R

4/(3*10) + 1/v2 = (1 - 4/3)/(-5)

1/v2 = 1/15 - 4/30

1/v2 = -2/30

v2 = -15 cm = final image distance from spherical window

So we can see that

image will be virtual (Since negative), 15 cm behind the window (Since negative)

Now magnification will be

M = m1*m2*m3

m1 = m3 = -n1*v/(n2*u),

m2 = -v/u

M = [-1*40/(4*30/3)]*[-(-15)/15]*[-(4/3)*(-15)/(1*10)]

M = -2

So image will be inverted and double sized.

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