What am I doing wrong here? 1 Near the surface of Earth, an electric field point

Question

What am I doing wrong here?

1 Near the surface of Earth, an electric field points radially downward and has a magnitude of approximately 100 NK. 1) What charge (magnitude and sign) would have to be placed on a penny that has a mass of 3.11 g to cause it to rise into the air with an upward acceleration of 1.990 m/s22 (Express your answer to three significant figures.) 367 You currently have 9 submissions for this question. Only 10 submission are allowed. You can make 1 more submissions for this question. mC Submit Your submissions: .367 x Computed value: .367 Submitted: Wednesday, September 12 at 5:11 PM Feedback:

Explanation / Answer

F = qE

Again F = ma

So, ma = qE

or, q = ma/E

Now, m = 3.11gm = 3.11 * 10-3kg

Therefore, q = (3.11 * 10-3 * 1.990)/100 = 6.1889 * 10-5 C = 0.061889 mC = 0.062 mC (3 significant figures)

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