Pad @49% webassign.net 2D Motion (Ch 4) Watch It Player | Cengage Learning Ch4,

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Pad @49% webassign.net 2D Motion (Ch 4) Watch It Player | Cengage Learning Ch4, solns.pd o Show My Work (optional 20. Question Details SerPSE10 4.4.OP.021 My Notes Ask Your Teach NASA's Ames Research Center in Mountain View, California, houses a 20g centrifuge used to conduct research and training to solve real world problems related to the effects of acceleration on systems. It consists of a horizontal rail system with a 58-foot diameter mounted on a central axis, as shown in the figure below. An astronaut is using the centrifuge for training on high accelerations during spaceflight. The astronaut is seated 29.0 ft from the axis of rotation. At what rotation rate, in revolutions per second, will the astronaut experience a centripetal acceleration of 18.7g? rev/s Need Help? Readi o Show My Work (ptionan)

Explanation / Answer

As we know that centripetal force is defined by

F = m* v2/r ; v is linear velocity and v can be represented by

v = * r ; is angular speed (in rad/s)

so, F = m* 2 * r

So, centripetal acceleration, a = F/m = (m* 2 * r) /m =  2 * r

As we need;

a = 18.7 * g ;

2 * r = 18.7 * g

= Square root of ( 18.7 * g / r)  

Here r = 29 ft and g = 32.174 ft / s2

= Square root of ( 18.7 * 32.174 / 29) = 4.555 rad/s

Revolution per second = /(2*pi()) = 4.555/ (2*pi()) = 0.725 rev/s

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