Ice and Silver 1 2 A 4.4-kg block of ice originally at 263 K is placed in therma

Question

Ice and Silver 1 2 A 4.4-kg block of ice originally at 263 K is placed in thermal contact with a 14.5-kg block of silver (CAg-233 J/kg-K) which is initially at 1011 K. The H20 silver system is insulated so no heat flows into or out of it. 1) At what temperature will the system achieve equilibrium? K| Submit You currently have O submissions for this question. Only 10 submission are allowed You can make 10 more submissions for this question. 2) What will be the phase of the H20 at equilibrium? OSolid (ice) Liquid (water) O Gas (vapor) Submit You currently have O submissions for this question. Only 10 submission are allowed You can make 10 more submissions for this question

Explanation / Answer

Here

1)

heat lost by silver = heat gain by ice

let the final temperature is T

4.4 * (2100 + 10 + 334 *10^3 + 4186 * (T - 273)) = 14.5 * 233 * (1011 - T)

solving for T

T = 319.5 K

the equilibrium temperature is 319.5 K

2)

the phase of H2O is

LIquid (water )

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