A 1530 kg rocket is to be launched with an initial upward speed of 54.0 m/s . In
ID: 1879080 • Letter: A
Question
A 1530 kg rocket is to be launched with an initial upward speed of 54.0 m/s . In order to assist its engines, the engineers will start it from rest on a ramp that rises 53 above the horizontal (the figure (Figure 1)). At the bottom, the ramp turns upward and launches the rocket vertically. The engines provide a constant forward thrust of 2000 N, and friction with the ramp surface is a constant 500 N.
Part A
How far from the base of the ramp should the rocket start, as measured along the surface of the ramp?
A 1530 kg rocket is to be launched with an initial upward speed of 54.0 m/s . In order to assist its engines, the engineers will start it from rest on a ramp that rises 53 above the horizontal (the figure (Figure 1)). At the bottom, the ramp turns upward and launches the rocket vertically. The engines provide a constant forward thrust of 2000 N, and friction with the ramp surface is a constant 500 N.
Part A
How far from the base of the ramp should the rocket start, as measured along the surface of the ramp?
Explanation / Answer
Using law of conservation of energy,
K1 + U1 + W = K2 + U2
0 + mgh + FL = 0.5 mv^2
(mgL sin53) + (Fthrust - ffriction ) L = 0.5 mv^2
L = (1530 x 54^2)/ 2[(1530 x 9.8 x sin53) + (2000 - 500)]
L = 165.55 m
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