a towplane towsa glider weighing 700 pounds from a field elevation of 6000 feet
ID: 1879654 • Letter: A
Question
a towplane towsa glider weighing 700 pounds from a field elevation of 6000 feet MSL to an altitude of 9000 feet MSL. The glider releases from two and establishes an airspeed of 60 knots.
what is the potential energy of the glider?
A) 6,300,000 ft-pounds
B) 112,000 ft-pounds
C) 2,100,000 ft-pounds
What is the kinetic energy of the glider?
A) 112,460 ft-pounds
B) 1,260,000
C) 2,210,000 ft-pounds
what is the total energy of the glider?
A) 6,412,458 ft-pounds
B) 2,212,459 ft-pounds
C) 4,300,000 ft-pounds
Explanation / Answer
1] difference in height = 9000 - 6000 = 3000 ft
weight = 700 pounds
the potential energy of the glider is:
U = Wh = 700 x 3000 = 2,100,000 ft-pounds.
2]
Kinetic energy = (1/2)mv2
where m = 700/32.15 lb
60 knots = 101.27 ft/s
so, Kinetic energy = (1/2)(700/32.15)(101.27)2 = 112,460 ft-pounds
Total energy = Kinetic Energy + Potential Energy = 2212459 ft-pounds.
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