You have 2 days left in your Cengage Unlimined subscription trial. Leam more for

Question

You have 2 days left in your Cengage Unlimined subscription trial. Leam more for less with access to over 22,000 ebooks and digital learning products. Upgrade Today, My Notes 1. 9.s3/11.11 points I Previous Arswers Giancol7 3 P059 A projectile is shot from the edge of a ciff h-305 m above ground level with an initial speed of vo -105 m/s at an angle of 37.0° with the horizontal, as shown in the figure below (a) Determine the time taken by the projectile to hit point P at ground level. 16.6 (b) Determine the range X of the projectile as measured from the base of the cliff 1.3944 (c) At the instant just before the projectile hits point P, find the horizontal and the vertical components of its velocity. (Take up and to the right as positive directions.) horizontal 4 vertical 99.75 (d) What is the the magnitude of the velocity? km x m/s 130.40 (e) What is the angle made by the velocity vector with the horizontal? m/'s (below the horizontal) (1) Find the maximum height above the ciff top reached by the projectile 202.4

Explanation / Answer

I see that you have already solved all the parts except vertical component of velocity in part (c)

You can calculate that by using kinematics

vy = vyo - gt

vyo = 105*sin 37 = 63.1905 m/s

vy =  63.1905 - 9.8*16.6

  vy = -99.489 m/s

NOTE - Do not forget the negative sign.

Related Questions

Navigate

• Browse (All)
• Browse Y
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.