2. (20) For the following questions, imagine that you throw a basebail up in the

Question

2. (20) For the following questions, imagine that you throw a basebail up in the air. As an approximation, you can ignore your height in the calculations. a. At what minimum speed must you throw the ball in order for it to reach a height of 15 m? b. What is the total time the ball in part a. spends in the air? e. What is the minimum launch speed required to reach a height of 15 m if you throw the ball at 50 above the horizontal instead? d. How much time does the ball in part e. spend in the air? e. What is the range for the ball in part e, assuming the ground is perfectly flat?

Explanation / Answer

A) V^2 - u^2 = 2gh

0 -u^2= 2×9.8×15

u= 17.146m/s

B) v = u + gt

0 = 17.146 - 9.8 ×t

17.146 = 9.8t

t= 1.749m/s

C) V^2 - u^2= 2gh ( in y direction)

0 - usin 50^2= 2 × 9.8 × 15

u sin 50 =17.146

u = 22.38m/s

D) v = u -gt ( in y direction)

0= u sin50 - 9.8t

t= u sin50/9.8

Total time = 2t = 2 × usin50/ 9.8= 2× 17.146/9.8= 3.499s

E) x = ucos50 × T = 22.38 cos50 × 3.499= 50.35m

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