i I need help with part B!!!!! thank you :) Class Help Homework 3 Begin Date: 9/

Question

i

I need help with part B!!!!! thank you :)

Class Help Homework 3 Begin Date: 9/5/2018 2:30:00 PM - - Due Date: 9/18/2018 11:59:00 PM End Date: 9/19/2018 4:00:00 AM (11%) Problem 9: A dart is launched at ground level with an initial speed of 41 m/s, at an angle of 27" above the horizontal. It strikes a mark above the ground 2.3 seconds later 50% Part (a) What is the horizontal distance, in metres, from where the dart was launched to where it lands? x 84.02 Correct! 50% Part (b) What is the vertical distance, in meters, from where the dart was launched to where it lands? Grade Summary Potential Submissions 5% 95% sin0 tan() | | ( | cos cotanasinO acos(O atan acotan sinh(0 cosh0tanhOcotanh0 Attempts remaining: 11 % per attempt) detailed view 1 23 0 5% END ODegrees O Radians DELI CLEAR Submit Hint I give up! Hints: 1 %-deduction per hint. Hints remaining: 3 Feedback: 2% deduction per feedback. All content © 2018 Expert T, LLC

Explanation / Answer

a)
Horizontal component of velocity vh = 41 * cos 27 = 36.53 m/s

time taken = 2.3 s

acceleration in horizontal is 0

Horizontal distance = vh*t = 36.53*2.3

Horizontal distance = 84.02 m

b)

vertical component of velocity vv = 41 * sin 27 = 18.61 m/s
time taken = 2.3 s
acceleration in horizontal is -9.8 m/s2

use:
d= vv*t + 0.5*a*t2

d = 18.61*2.3 +0.5*(-9.8)*(2.3)2

d = 16.89 m

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