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C sign In or Sign Up IChec x West Liberty: My Works: x QuIz Chapter 2 Secure Ihttps:/sakai westlbery eda/ samgo-appsfrdedivery/begin taking 2 TakingAssessment faces A car starting from rest moves with constant acceleration of 5.0 m/s? for 10 s, then travels with c of -2.0 m/s?. The total distance it travels is - 0 m/st for 10 s, then travels with constant speed for another 20 s, and then finally slows to a stop with constant acceleration Mark for Review What's This? Question 8 of 10 10.0 Points A car starting from rest moves with constant acceleration of 5.0 m/s2 for 8 s, then travels with constant speed for another 1 hour, and then finally slows to a stop with constant acceleration of -3.0 m/s2. The total distance it travels is Mark for Review Whats Thie km Part 3 of 3 Question 9 of 10 10.0 Points If you travel 120 miles with an average speed of 27 m/s, your travel time is + Mark for Review What's T Question 10 of 10 10.0 Points +3 7:23. Guest acer

Explanation / Answer

1)

Distance covered during accelerated motion

D1= 0.5 x 5 x 10^2= 250 m

Final velocity after 10 seconds of accelerated motion

V = at = 5 x 20 = 100 m/s

Now for steady speed, distance travelled by object

D2= vt= 100 x 20 = 2000 m

For deaccelerated motion,

Applying 3rds equation of motion

D3= V^2/(2*a)= 100^2/(2*2)= 2500 m

Total distance travelled = 250+2000+ 2500= 4750 m

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