12) What is its radius of curvature of particle #1 in the magnetic field? 345 m

Question

12)  What is its radius of curvature of particle #1 in the magnetic field?

345 m

697 m

1200 m

1650 m

1983 m

13)  A uniform electric field is now applied in the region of the magnetic field so that particle #1 continues to move up vertically without bending. What should be the direction of this electric field?

right

left

up

down

into the page

out of the page

14)  What should be the magnitude of this electric field?

600 N/C

700 N/C

800 N/C

900 N/C

Explanation / Answer

You have omitted the first part of question in which mass, charge and velocity were given. Writing in terms of formula, please put the values in below formulas.

12)

Radius, r = mv/qB

Here, m = mass (kg)

V = velocity (m/s)

q = charge (Coulomb)

B = magnetic field (T)

13)

Field should be directed to the right.

14)

Electric field, E = F/q

Here, F = force = q x v x B

q = charge

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